Arizona State University CHM 114 Sample Final Exam and Answers - \ CHM 114 Final Exam Practice Exam Instructor: O. Graudejus Points: 200 Print Name Sign Name Student I.D. # 1.
Print Name
Sign Name
Student I.D. #
1. You are responsible for the information on this page. Please read it carefully.
2. Code your name and 10 digit affiliate identification number on the separate scantron answer sh
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Arizona State University CHM 114 Sample Final Exam and Answers - \ CHM 114 Final Exam Practice Exam Instructor: O. Graudejus Points: 200 Print Name Sign Name Student I.D. # 1.
Print Name
Sign Name
Student I.D. #
1. You are responsible for the information on this page. Please read it carefully.
2. Code your name and 10 digit affiliate identification number on the separate scantron answer sheet. Use only a #2
pencil
3. Do all calculations on the exam pages. Do not make any unnecessary marks on the answer sheet.
4. This exam consists of 50 multiple choice questions worth 4 points each and a periodic table. Make sure you have
them all.
5. Choose the best answer to each of the questions and answer it on the computer-graded answer sheet. Read all
responses before making a selection.
6. Read the directions carefully for each problem.
7. Avoid even casual glances at other students’ exams.
8. Stop writing and hand in your scantron answer sheet and your test promptly when instructed. LATE EXAMS
MAY HAVE POINTS DEDUCTED.
9. You will have 110 minutes to complete the exam.
10. If you leave early, please do so quietly.
11. Work the easiest problems first.
12. A periodic table is attached as the last page to this exam.
13. Answers will be posted online this afternoon.
Potentially useful information:
K = ºC + 273.15
R=8.314 J·K-1·mol-1
c=3·108 m/s
h=6.626·10-34 Js |
PV=nRT
∆E = q + w
Ephoton=h·ν=h·c/λ
760 torr = 1 atm = 101325 Pa = 1.013 bar |
Avogadro’s Number = 6.022 × 1023 particles/mole
∆H°
rxn = ∑ n ∆Hf° (products) - ∑ n ∆Hf° (reactants) |
| q = (Sp. Heat) × m × ∆T |
(Specific Heatwater = 4.184 J/g°C) |
| Dalton Law: Ptotal = P1+P2+P2+…; |
P1=X1·P10 |
∆G = ∆H - T∆S
∆G° = -RT lnK
∆H°
rxn = ∑(bond enthalpies of broken bonds) - ∑(bond enthalpies of bonds formed)
∆S° = ΣnS°products - ΣnS°reactants
∆S
vap = ∆Hvap/Tboil, ∆Sfus = ∆Hfus/Tmelt
E°rxn =E°cell = E°ox + E°red
∆G°= -nFE°
Zero order: -∆[A]/∆t = k,
[A] = [A]o - kt,
t½ = [A]o/2k
First order: -∆[A]/∆t = k[A],
ln[A] = ln[A]o - kt,
t½ = 0.693/k
Second order: -∆[A]/∆t = k[A]2,
[A]-1 = [A]o-1 + kt,
t½ = 1/k[A]o
k = Ae-Ea/RT
K
p =
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