Genome 361, 9 April 2020, Lecture 4

Lecture Materials > Genome 361, 9 April 2020, Lecture 4

University of Washington GENOME 361 More Mendel & Sex-linked inheritance Exam next Thursday! Covers lectures 1-5, quiz sections 1-3, & problem sets 1-3 Exam is meant to be 80 minutes long, but to facilitate online exam-taking, you will be given 110 minutes, and you can take the exam between 8:30 am and 12:30 pm. Have a calculator handy. ...[Show More]

University of Washington
GENOME 361
More Mendel & Sex-linked inheritance

Exam next Thursday!

Covers lectures 1-5, quiz sections 1-3, & problem sets 1-3

Exam is meant to be 80 minutes long, but to facilitate online exam-taking, you will be given 110 minutes, and you can take the exam between 8:30 am and 12:30 pm.

Have a calculator handy.

During the exams, you must do your own work, and any form of communication with classmates or the use of internet resources other than your class notes is not allowed. Slides and any other handouts are ok to use.

Practice exam and early handouts for next week will be posted soon. Note that these cover next week’s material too, so work what you can in the meantime.

Sticking with zoom quiz sections for next week.

Don’t forget about Canvas.

Genome 361, 9 April 2020, Lecture 4

Sex-linked inheritance

Topics today

>Sex linkage >Mitochondrial inheritance

Genome 361, 9 April 2020, Lecture 4

X-linked disorders http://www.ncbi.nlm.nih.gov/books/NBK21257/#A528

Sex linkage in flies http://www.ncbi.nlm.nih.gov/books/NBK22088/#A475

X inactivation

(also some optional epigenetics for those interested) http://www.ncbi.nlm.nih.gov/books/NBK26854/#A1347

Supplemental readings A quick refresher

P short haired, agouti x long haired, non-agouti

F1 What’s dominant?

All short haired, agouti

Predicting probabilities: a new cross

AaLl x aaLl A = agouti a = non-agouti L = shortl = long

What is the probability of getting a long-haired agouti kitten out of

(Mom) (Dad)

this new cross?

Gametes needed: Genotype needed:

Mom:

Dad:

Probability = Probability =

Probability of genotype =

Predicting probabilities of outcomes

AaLl x aaLl A = agouti a = non-agouti L = shortl = long

What is the probability of getting a long-haired agouti kitten out of

this new cross?

Gametes needed: Genotype needed:

Mom:

Dad:

Aa ll Al

al

Probability = 1/4

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Category:	Lecture Materials
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Language:	English
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AaLl x aaLl	A = agouti a = non-agouti L = shortl = long
What is the probability of getting a long-haired agouti kitten out of
(Mom)	(Dad)