Phys2BL Lab 4.University of California, San DiegoPHYS 2BLResults and Analysis Error Propagationo v =ltδv=√( δv δl δl)2+( δv δt δt)2δvδl =1tδl=0.0002 mδvδt =-lt2 δt=√0.052+√22=1.4 so pi=m1 v1+m2 v2=m1v1+0=m1 v1δ pi=√( δδmpi 1 δ m1)2+( δδ vp1i δ v1)2δpδm =v δm=0.00005 kgδpδv =m δv=√( δv δl δl)2+( δv δt δt)2o pf =(m1+m2)v f ...[Show More]
Category: | Lab Experiment |
Number of pages: | 10 |
Language: | English |
Last updated: | 1 year ago |
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