University of Ontario Institute of Technology MECE 2230U Q1 Given; P = (−160?̂+ 40?̂+ 60?̂)N Distance (d) between point O and A is 8m. a) Magnitude of vector P; |P| = √(−160) 2 + 402 + 602 |P| = 175.499 N From the direction cosines; P⃗ = Pcos???̂+ Pcos???̂+ Pcos???̂ Pcos?? = −160 cos?? = − 160 175.499 = −0.912 ?? = 155.74° ?? 24.26° Pcos?? = 40 cos?? = 40 175 ...[Show More]
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