Assignment-01.  Wayne State University CSE 5301

NISARG PAWAR
STUDENT ID: 1001720812
CSE5301 Homework-1
DATA:
There are three rooms in a house: the kitchen, the bedroom and the living room.
There is a radio transmitter outside the home that can be received in each room. A user
is wearing a device that can measure the strength of the signal; however, due to noise
in the sensor and in the environment, each time the device reads the signal strength,
the result may contain an error. We know that the bedroom should have a reading of 50
units; the kitchen a reading of 51 units; and the living room a reading of 52 units in 50%
of the cases and 53 in the other 50% of the cases. Someone has made a lot of
measurements and created the following table representing the probability distribution
for a given reading is in a particular room (P(Reading|Room)):

Solution:
Here Let,
Bedroom = B
Kitchen = K
Living Room = L
and P(B) = P(K) = P(L) = ⅓ (Probability of picking a room at random)
(A)
Solution:​ Here we need to calculate P(B|52), P(L|52) and P(L|52).
We have:
P(52|B) = 0.08
P(52|K) = 0.14
P(52|L)